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3.14x^2+31.4x=1250
We move all terms to the left:
3.14x^2+31.4x-(1250)=0
a = 3.14; b = 31.4; c = -1250;
Δ = b2-4ac
Δ = 31.42-4·3.14·(-1250)
Δ = 16685.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31.4)-\sqrt{16685.96}}{2*3.14}=\frac{-31.4-\sqrt{16685.96}}{6.28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31.4)+\sqrt{16685.96}}{2*3.14}=\frac{-31.4+\sqrt{16685.96}}{6.28} $
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